Saved Bookmarks
| 1. |
If (2.3)^x=(0.23)^y=1000, then find the value of 1/x-1/y please.. |
|
Answer» Answer: Step-by-step explanation: Apply logarithms: 2.3^x = 0.23^y = 1000 x Log 2.3 = y Log 0.23 = Log 1000 x Log 2.3 = y (Log 2.3/10 ) = 3 x Log 2.3 = y (Log 2.3 - Log 10) = 3 1/x = (Log 2.3)/3 1/y = (Log 2.3 -1)/3 = (Log 2.3)/3 - 1/3 1/y = 1/x - 1/3 |
|