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if 2*10^-3 jouls in moving a particle carrying a charge of 10*10^-6 C from infinity to a point P, what will be the potential at the point P? |
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Answer» If 1 Coulomb charge is MOVED across a potential difference of 1 Volt; the work DONE in the process equals 1 Joule.Thus, 1 Joule = 1 Coulomb * 1 Volt.Here, work done = 3 * 10^(-3) JouleCharge = 15 * 10^(-6) CoulombPotential at infinity = 0 Volt |
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