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If 2(1+tanα+tan2α+⋯∞)=√3+1, where 0<α<π4, then the sum of the solutions of the equation sinθ=sinα in [0,4π] is equal to |
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Answer» If 2(1+tanα+tan2α+⋯∞)=√3+1, where 0<α<π4, then the sum of the solutions of the equation sinθ=sinα in [0,4π] is equal to |
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