If ∫1x√1−x3dx=alog∣∣∣√1−x3−1√1−x3+1∣∣∣+b, then 6a is equal to(log is taken on natural base ′e′ and C is constant of integration)

If ∫1x√1−x3dx=alog∣∣∣√1−x3−1√1−x3+1∣∣∣+b,

1.	If ∫1x√1−x3dx=alog∣∣∣√1−x3−1√1−x3+1∣∣∣+b, then 6a is equal to(log is taken on natural base ′e′ and C is constant of integration)
Answer» If $\int \frac{1}{x \sqrt{1 - x^{3}}} d x = a log ∣ ∣ ∣ \frac{\sqrt{1 - x^{3}} - 1}{\sqrt{1 - x^{3}} + 1} ∣ ∣ ∣ + b,$ then $6 a$ is equal to $(log is taken on natural base^{'} e^{'}$ and $C$ is constant of integration)

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If ∫1x√1−x3dx=alog∣∣∣√1−x3−1√1−x3+1∣∣∣+b, then 6a is equal to(log is taken on natural base ′e′ and C is constant of integration)

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