If 1st ionization energy of Li(g) is 5.39 eV and Li(g)→Li3+(g)+3e� – InterviewSolution

1.	If 1st ionization energy of Li(g) is 5.39 eV and Li(g)→Li3+(g)+3e− ΔH=+203.43 eV Then the ionisation energy of Li+ is
Answer» If $1^{s t}$ ionization energy of $L i (g)$ is 5.39 eV and $L i_{(g)} \to L i_{(g)}^{3 +} + 3 e^{-} Δ H = + 203.43 e V$ Then the ionisation energy of $L i^{+}$ is

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