1.

If 1500g of an object is moving with 60km/hr.Calculate the work done in which it allows to stop it.

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m=1500kg U= 60km/h =60* 5/18 = 50/3m/s V =0m/s w = change in its KE. INITIAL KE =1/2 mu2 final KE=1/2mv² w = 1/2mv2  - 1/2 mu2   =1/2m(v2-u2) = 1/2 * 15000{0- (50/3)2} =  -208333.33J


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