1.

If 120 g steam of temperature 100 ∘C is released on an ice slab of temperature 0 ∘C, how much ice will melt? (Latent heat of melting of ice = 80 cal/g Latent heat of vapourization of water = 540 cal/g)

Answer»

If 120 g steam of temperature 100 C is released on an ice slab of temperature 0 C, how much ice will melt?
(Latent heat of melting of ice = 80 cal/g
Latent heat of vapourization of water = 540 cal/g)



Discussion

No Comment Found

Related InterviewSolutions