If 12 furnaces consume 13 tonnes of coal in $6\frac{1}{2}$ hours, h

1.	If 12 furnaces consume 13 tonnes of coal in \(6\frac{1}{2}\) hours, how long will 7 furnaces be consuming 14 tonnes?1). 11 hrs2). 10 hrs3). 12 hrs4). 15 hrs
Answer» Concept: If M₁Persons can do a work W₁ in H₁ hours and M₂ persons can do a work W₂in H₂hours then we have a general formula in this case. $(\frac{{{M_1}{H_1}}}{{{W_1}}} = \frac{{{M_2}{H_2}}}{{{W_2}}})$ If 12 furnaces consume 13 tonnes of coal in $(6\frac{1}{2})$ hours, then for 7 furnaces for consuming 14 tonnes We have, M₁ = 12 furnaces W₁= 13 tones H₁ = $(6\frac{1}{2} = \frac{{13}}{2}\;hours)$ M₂ = 7 furnaces W₂ = 14 tones Let H₂ = H hours By putting all these values in the above general formula $(\begin{array}{l} \frac{{12 \times \frac{{13}}{2}}}{{13}} = \frac{{7 \times H}}{{14}}\\ \RIGHTARROW \;H\; = \frac{{12 \times 13 \times 14}}{{2 \times 7 \times 13}} = 12hours\; \end{array})$

If 12 furnaces consume 13 tonnes of coal in $6\frac{1}{2}$ hours, how long will 7 furnaces be consuming 14 tonnes?1). 11 hrs2). 10 hrs3). 12 hrs4). 15 hrs

Answer»

Concept: If M₁Persons can do a work W₁ in H₁ hours and M₂ persons can do a work W₂in H₂hours then we have a general formula in this case.

$(\frac{{{M_1}{H_1}}}{{{W_1}}} = \frac{{{M_2}{H_2}}}{{{W_2}}})$

If 12 furnaces consume 13 tonnes of coal in $(6\frac{1}{2})$ hours, then for 7 furnaces for consuming 14 tonnes

We have, M₁ = 12 furnaces

W₁= 13 tones

H₁ = $(6\frac{1}{2} = \frac{{13}}{2}\;hours)$

M₂ = 7 furnaces

W₂ = 14 tones

Let H₂ = H hours

By putting all these values in the above general formula

$(\begin{array}{l} \frac{{12 \times \frac{{13}}{2}}}{{13}} = \frac{{7 \times H}}{{14}}\\ \RIGHTARROW \;H\; = \frac{{12 \times 13 \times 14}}{{2 \times 7 \times 13}} = 12hours\; \end{array})$

Discussion

No Comment Found

Related InterviewSolutions

Pipe A can fill the tank in 45 min and pipe B can empty the tank in 1 hour 30 min. If pipe B is opened after 30 min of start of pipe A, what is the total time required to fill the tank?1). 1 hour2). 1 hour 10 min3). 1 hour 20 min4). 1 hour 30 min
1). 502). 443). 564). 54
A man is twice as fast as a woman and a woman is twice as fast as a boy. If all of them i.e. a man, a woman and a boy can finish a work together in 4 days, in how many days a boy shall do it alone?1). 28 days2). 21 days3). 14 days4). 7 days
Quantity B: B can complete the work in 20 days. C is twice as efficient as B and A takes 2 days more than C to complete the work. Working together, in how much time would they be able to complete the work?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B
96 men can complete a work in 40 days. They all worked for 10 days. But to finish the work before time, contractor brought N more men to work. Because of this, the work got finished in a total of 34 days. What is the value of N?1). 162). 203). 244). 27
Kamal can do a work in 20 days. Bimal is 20% more efficient than Kamal. Suresh is 25% more efficient than Bimal. The number of days, Suresh will take to do the same piece of work, is1). 16 days2). 12 days3). $15\frac{2}{3}$ days4). $13\frac{1}{3}$ days
A is 25% more efficient then B. A works for ‘D’ days and completed 1/3 of work and left the work and remaining work is completed by B in ‘D + 12’ day. In how many days A and B together can complete the work.1). 15 days2). $13\frac{1}{3}days$3). 12 days4). $12\frac{1}{3}days$
1). 60/11 hours2). 60/17 hours3). 30/23 hours4). 24 hours
Nikhil is thrice as efficient as Kanak and can finish an assignment in 6 days less than Kanak. How many days Kanak will take to finish the same assignment?1). 4 days2). 7 days3). 9 days4). 11 days
1). 14 hours2). 42 hours3). 35 hours4). 70 hours