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If 10gm of ice 0 degree Celsius is mixed with 10gm of steam 100 degree Celsius

Answer»

please make me as BRAINLIST pleaseExplanation:solution Heat absorbed by ice =mL F +ms△Tice△Q absorb =(10)(80)+(10)(1)(T−0)Heat released by water = M8 △T water △Q release = 10(1)(100-T)NOTE : △T ice is the TEMPERATURE changein water that has been converted from water.So, △Q absorb = △Q release⇒800+10T=1000−10T⇒T=10 ∘ COption - B is correct.



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