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If `100 mL "of" 1 M H_(2) SO_(4)` solution is mixed with `100 mL` of 98% `(W//W)` of `H_(2)SO_(4)` solution `(d = 0.1 g mL^(-1))`, thenA. concentration of solution remains sameB. volume of solution become 200 mlC. mass of `H_2SO_4` in the solution is 98 gmD. mass of `H_2SO_4` in the solution is 19.6 gm |
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Answer» Correct Answer - A,B,D (A)Molarity of second solution is `=(10xxdxxx)/M=1M` (B)Volume=100+100=200 ml ( D)Mass of `H_2SO_4=(200xx1)/1000xx98=19.6` gm |
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