1.

If 10^2y=25, then wat is 10^-y

Answer»

{10)^y }² = 5²

=> if POWERS are EQUAL , BASES are equal

=> 10^y = 5

=> then ,

• 10^-y = 1 / 10^y = 1/5

{ same as , 2^-1 = 1/2 }



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