1.

If (1−y)(1+2x+4x2+8x3+16x4+32x5)=1−y6, where y≠1,x≠12, then the value of yx is

Answer»

If (1y)(1+2x+4x2+8x3+16x4+32x5)=1y6, where y1,x12, then the value of yx is



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