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If 1 upon 3 of a number exceeds its 2 upon 7 by 1 find the number |
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Answer» LET the NUMBER be X. 1/3 of x= x/3 EXCEEDS its 2/7 i.e. 2x/7 by 1 Therefore x/3=2x/7+1 = x/3=2/7+7/7 =7x=6x+21 = x= 21 |
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