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If `[(1,-tan theta),(tan theta,1)][(1,tan theta),(-tan theta,1)]^(-1)=[(a,-b),(b,a)],` thenA. `a=cos 2 theta, b = sin 2 theta `B. `a=1, b=1`C. `a=sin 2 theta, b=cos 2 theta `D. `a=sec 2 theta, b=tan 2 theta `

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