If ∣∣∣∣∣1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2 – InterviewSolution

1.	If ∣∣∣∣∣1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2θ1+4sin4θ∣∣∣∣∣=0 such that 0≤θ≤π2 then θ is
Answer» If $∣ ∣∣∣ ∣ \begin{matrix} 1 + s i n^{2} θ & c o s^{2} θ & 4 s i n 4 θ s i n^{2} θ & 1 + c o s^{2} θ & 4 s i n 4 θ s i n^{2} θ & c o s^{2} θ & 1 + 4 s i n 4 θ \end{matrix} ∣ ∣∣∣ ∣ = 0$ such that $0 \leq θ \leq \frac{π}{2}$ then $θ$ is

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