If 1 + sin2 = 3 sincos e, then prove that tan 0 = 1 or tan 0 = – InterviewSolution

1.

If 1 + sin2 = 3 sincos e, then prove that tan 0 = 1 or tan 0 =

Answer»

1++sin^2A=3sinAcosA , divide both side by cos^A.

sec^2A+tan^2A=3tanA

1+tan^2A+tan^2A=3tanA

2tan^2A-3tanA+1=0

2tan^2A-2tanA-tanA+1=0

2tanA(tanA-1)-1(tanA-1)=0

(tanA-1)(2tanA-1)=0

Either tanA-1=0

tanA=1 , proved

Or 2tanA-1=0

tanA= 1/2 (possible value).

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