1.

If 1,log10(4x−2) and log10(4x+185) are in arithmetic progression for a real number x, then the value of the determinant ∣∣∣∣∣∣2(x−12)x−1x210xx10∣∣∣∣∣∣ is equal to

Answer» If 1,log10(4x2) and log10(4x+185) are in arithmetic progression for a real number x, then the value of the determinant


2(x12)x1x210xx10


is equal to


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