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If 1 is zero of the polynomial p(x)=ax^2-3(a-1)x-1,then find the valueof a |
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Answer» ong>Answer: now p(1) = a(1)^2 - 3(a-1)(1)-1 =a(1) - 3(a-1)-1 = a-3a+3-1 = -2a +2 = -2a = -2 so cutting the negative sign both side 2a= 2 dividing by 2 to both side a= 1 |
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