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If ∫1−(cotx)2008tanx+(cotx)2009dx=1kln∣∣sinkx+coskx∣∣+C for arbitrary constant of integration C, then the value of k is |
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Answer» If ∫1−(cotx)2008tanx+(cotx)2009dx=1kln∣∣sinkx+coskx∣∣+C for arbitrary constant of integration C, then the value of k is |
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