1.

If ∫1−(cotx)2008tanx+(cotx)2009dx=1kln∣∣sinkx+coskx∣∣+C for arbitrary constant of integration C, then the value of k is

Answer»

If 1(cotx)2008tanx+(cotx)2009dx=1klnsinkx+coskx+C for arbitrary constant of integration C, then the value of k is



Discussion

No Comment Found