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If 1-3 is one root ofthe quadratic equation r2-2kr-6 = 0, then find the value of k2 |
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Answer» Given it's one root of the equation x² - 2kx - 6 = 0 one of its root x = 3 for finding the value of k put the value of x in this equation. (3)² - 2k(3) - 6 = 0 9 - 6k - 6 = 0 6k = 3 k = 3/6 k = 1/2 hence,the value of k = 1/2 |
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