1.

If 1/(√2 + 1 )+ 1/(√3+√2) =a+b√3 find the value of a^3+b^3.i will mark brainliest​

Answer»

ANSWER:

a^3 + b^3 = 0

Step-by-step explanation:

RATIONALISE the denominators,

1/(√2+1)×(√2-1)/(√2-1)

= (√2-1)/(√2)^2 -1^2

=(√2-1)/1

=√2-1

1/(√3+√2)×(√3-√2)/(√3-√2)

=(√3-√2)/(√3)^2 -(√2)^2

=(√3-√2)/1

=√3-√2

(√2-1)+(√3-√2) = a+b√3

=√2-1+√3-√2 = a+b√3

= √2-√2 -1 +√3 = a+b√3

-1 + 1√3 = a+b√3

Therefore, a = -1

b = 1

a^3 + b^3

= (-1)^3 +1^3

= -1 + 1

= 1-1

= 0


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