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If 1.11 g Mg2P2O7 is formed at the end of the reaction, then what weight of NaH2PO4 was present originally given that no other products contained phosphorus? (Molar mass Mg2P2O7=222 g mol−1, NaH2PO4=120 g mol−1) NaH2PO4+Mg2++NH+4→Mg(NH4)PO4.6H2O→Mg2P2O7 |
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Answer» If 1.11 g Mg2P2O7 is formed at the end of the reaction, then what weight of NaH2PO4 was present originally given that no other products contained phosphorus? (Molar mass Mg2P2O7=222 g mol−1, NaH2PO4=120 g mol−1) NaH2PO4+Mg2++NH+4→Mg(NH4)PO4.6H2O→Mg2P2O7 |
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