If 1(1/2)mole of oxygen combined with aluminium metal to form aluminum

1.	If 1(1/2)mole of oxygen combined with aluminium metal to form aluminum oxide, the weight of aluminum metalused in grams is (at .wt. of Al = 27)
Answer» Explanation: 2Al+ 2 3 O 2 →Al 2 O 3 2 3 molO 2 REQUIRES 2 MOLAL 1mol O 2 requires 3 2×2 molAl 2 1 mol O 2 requires 3 4 × 2 1 molAl = 3 2 mol = 3 2 ×27=18gm aluminum. Hence, option B is correct.

If 1(1/2)mole of oxygen combined with aluminium metal to form aluminum oxide, the weight of aluminum metalused in grams is (at .wt. of Al = 27)

Answer»

Explanation:

2Al+

→Al

molO

1mol O

requires

2×2

molAl

mol O

requires

molAl

mol

×27=18gm aluminum.

Hence, option B is correct.