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If 1(1/2)mole of oxygen combined with aluminium metal to form aluminum oxide, the weight of aluminum metal used in grams is (at .wt. of Al = 27) |
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Answer» ong>Explanation: 2Al+ 2 3
O 2
→Al 2
O 3
2 3
molO 2
REQUIRES 2 molAl 1mol O 2
requires 3 2×2
molAl 2 1
mol O 2
requires 3 4
× 2 1
molAl = 3 2
mol = 3 2
×27=18gm aluminum. |
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