1.

If 0

Answer» x=[x]+{x}
[x]=x-{x}
`[x/2]+[x/3]+[x/5]=(31x)/30`
`x/2-{x/2}+x/3-{x/3}+x/5-{x/5}=(31x)/30`
`x/2+x/3+x/5-[(x/2)+(x/3)+(x/5)]=(31x)/30`
`(3x)/30=t`
`t=0`
x is multiple of 2,3,5
LCM of(2,3,5)=30
x=30m
`0<30m<1000`
n=1to33
33 possibles values of x.


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