1.

If 0.5 mol of BaCl_(2) is mixed with 0.2 mole of Na_(3)PO_(4), the maximum number of moles of Ba_(3)(PO_(4))_(2) that can be formed is

Answer»

0.7
0.5
0.3
0.1

Solution :`3BaCl_(2)+2Na_(3)PO_(4) rarr Ba_(3)(PO_(4))_(2)+6NaCl`
`"3 moles of "BaCl_(2)" react with 2 moles of "Na_(3)PO_(4).Na_(3)PO_(4)" will be the LIMITING reactant."`


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