1.

IE1 and IE2 of Ca are 141 and 274 kcal respectively. The energy required for the following reaction is: Ca→Ca2++2e− (Where IE = ionization energy)

Answer» IE1 and IE2 of Ca are 141 and 274 kcal respectively. The energy required for the following reaction is:
CaCa2++2e
(Where IE = ionization energy)


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