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Identify the type of the function `f:R to R,` `f(x)=e^(x^(2))+cosx.` |
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Answer» Correct Answer - many-one,into `f(x)=e^(x^(2))+cosx` Clearly, `f(1)=f(-1),f(2)=f(-2)` etc. So, `f(x)` is many-one. Range of `e^(x^(2))` is `[1,oo)` and range of ` cos x " is " [-1,1].` Thus `f(x)` does not take negative values. Hence `f(x)` is into. |
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