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Identify the oxidising agent (oxidant) in the following reactions: (a) Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O (b) 2Mg + O2→ 2MgO (c) CuSO4 + Zn → Cu + ZnSO4 (d) V2O5 + 5Ca → 2V + 5CaO (e) 3Fe + 4H2O → Fe3O4 + 4H2 (f) CuO + H2→ Cu + H2O |
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Answer» Oxidizing agent: An oxidizing agent is an element that gains electrons. Since, the oxidizing agent means to gain electrons; it is said to have been reduced. The element which undergoes reduction (gets reduced) is called oxidizing agent. (a) Pb3O4 is reducing agent Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O In the given reaction, Pb3O4 loses oxygen and reduces to PbCl2. Thus, Pb3O4 is an oxidizing agent as it undergoes reduction. (b) O2 is oxidizing agent 2Mg + O2→ 2MgO In the given reaction, O2 is reduced by losing oxygen atoms. Thus, O2 is an oxidizing agent as it undergoes reduction. (c) CuSO4 is oxidizing agent CuSO4 + Zn → Cu + ZnSO4 In the given reaction, CuSO4 is reduced to Cu by losing oxygen atoms. Thus, CuSO4 is an oxidizing agent as it undergoes reduction. (d) V2O5 is oxidizing agent V2O5 + 5Ca → 2V + 5CaO In the given reaction, V2O5 is reduced to V by losing oxygen atoms. Thus, V2O5 is an oxidizing agent as it undergoes reduction. (e) H2O is oxidizing agent 3Fe + 4H2O → Fe3O4 + 4H2 In the given reaction, H2O is reduced to H2 by losing oxygen atoms. Thus, H2O is an oxidizing agent as it undergoes reduction. (f) CuO is oxidizing agent CuO + H2→ Cu + H2O In the given reaction, Cu is reduced to Cu by losing oxygen atom. Thus, CuO is an oxidizing agent as it undergoes reduction. |
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