1.

Identify the oxidising agent (oxidant) in the following reactions: (a) Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O (b) 2Mg + O2→ 2MgO (c) CuSO4 + Zn → Cu + ZnSO4 (d) V2O5 + 5Ca → 2V + 5CaO (e) 3Fe + 4H2O → Fe3O4 + 4H2 (f) CuO + H2→ Cu + H2O

Answer»

Oxidizing agent: An oxidizing agent is an element that gains electrons. Since, the oxidizing agent means to gain electrons; it is said to have been reduced.

The element which undergoes reduction (gets reduced) is called oxidizing agent. 

(a) Pb3O4 is reducing agent 

Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O

In the given reaction, Pb3O4 loses oxygen and reduces to PbCl2. Thus, Pb3O4 is an oxidizing agent as it undergoes reduction. 

(b) O2 is oxidizing agent 

2Mg + O2→ 2MgO 

In the given reaction, O2 is reduced by losing oxygen atoms. Thus, O2 is an oxidizing agent as it undergoes reduction. 

(c) CuSO4 is oxidizing agent 

CuSO4 + Zn → Cu + ZnSO4 

In the given reaction, CuSO4 is reduced to Cu by losing oxygen atoms. Thus, CuSO4 is an oxidizing agent as it undergoes reduction.

(d) V2O5 is oxidizing agent 

V2O5 + 5Ca → 2V + 5CaO 

In the given reaction, V2O5 is reduced to V by losing oxygen atoms. Thus, V2O5 is an oxidizing agent as it undergoes reduction. 

(e) H2O is oxidizing agent 

3Fe + 4H2O → Fe3O4 + 4H2

In the given reaction, H2O is reduced to H2 by losing oxygen atoms. Thus, H2O is an oxidizing agent as it undergoes reduction. 

(f) CuO is oxidizing agent 

CuO + H2→ Cu + H2O 

In the given reaction, Cu is reduced to Cu by losing oxygen atom. Thus, CuO is an oxidizing agent as it undergoes reduction.



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