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Ice at 0∘C is added to 1 g of steam at 100∘C. For x g of ice added, the temperature of steam reduces to 0∘C. Find the value of x. (Latent heat of ice =80 cal/g and latent heat of steam =540 cal/g. Also, specific heat of water =1 cal/ kg K) |
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Answer» Ice at 0∘C is added to 1 g of steam at 100∘C. For x g of ice added, the temperature of steam reduces to 0∘C. Find the value of x. (Latent heat of ice =80 cal/g and latent heat of steam =540 cal/g. Also, specific heat of water =1 cal/ kg K) |
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