iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25.

1.	iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25. p abody te beunds to a height op
Answer» answer is 12meters. initially when the body is dropped, u=0, distance travelled is 16m therefore final velocity before hitting the ground is v^2=u^2+ 2as v^2= 2x gx 16. since 25% kinetic energy is lost in collision, the energy left in the body is 75% therefore 75/100 x 1/2mv^2= mgh wherehis the distance to which it rebounds. m on both sides gets cancelled, on putting the value of v^2in the above equation you geth= 12m

iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25. p abody te beunds to a height op

Answer»

answer is 12meters.

initially when the body is dropped, u=0, distance travelled is 16m therefore final velocity before hitting the ground is

v^2=u^2+ 2as

v^2= 2x gx 16.

since 25% kinetic energy is lost in collision, the energy left in the body is 75%

therefore 75/100 x 1/2mv^2= mgh

wherehis the distance to which it rebounds.

m on both sides gets cancelled, on putting the value of v^2in the above equation you geth= 12m