I1=π2∫0sinx−cosx1+sinxcosxdx, I2=2π∫0cos6xdx,I3=π2∫−π2si – InterviewSolution

1.	I1=π2∫0sinx−cosx1+sinxcosxdx, I2=2π∫0cos6xdx,I3=π2∫−π2sin3xdx, I4=1∫0ln(1x−1)dx, then
Answer» $I_{1} = \frac{π}{2} \int 0 \frac{sin x - cos x}{1 + sin x cos x} d x, I_{2} = 2 π \int 0 {cos}^{6} x d x$ , $I_{3} = \frac{π}{2} \int - \frac{π}{2} {sin}^{3} x d x, I_{4} = 1 \int 0 ln (\frac{1}{x} - 1) d x$ , then

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