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I. ` x^(2) + 28x + 192 = 0` II. ` y^(2)+16y+48=0`A. `x gt y `B. `x ge y`C. ` x lt y`D. ` x le y` |
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Answer» Correct Answer - D I. ` x^(2) +28 x + 192 = 0` ` rArr x^(2) + 16x + 12x + 192 = 0` ` rArr x(x+16) + 12(x+16) = 0` ` rArr (x+12) (x+16) = 0` ` rArr x =- 12 or -16` II. `y^(2) + 16y+ 48 = 0` ` rArr y^(2) + 12y+ 4y+48 = 0` ` rArr y(y+12) + 4(y+12) = 0` ` rArr (y+12) (y+4) = 0` ` rArr y =- 12 or -4 ` Clearly, ` x le y ` |
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