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(i) The following frequency distribution table shows marks obtained by 180 students in Meexamination :MarksNumber of Students0-102510 - 20sox20 - 303030 - 402x ho40 - 5065Find the value of x.M = 180Also draw a histogram representing the above information. |
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Answer» The value of x is 20. The HISTOGRAM representing the above information is as shown below. Given, 0 - 10 25 10 - 20 x 20 - 30 30 30 - 40 2x 40 - 50 65 Total number of students M = 180 So, we have, 25 + x + 30 + 2x + 65 = 180 120 + 3x = 180 3x = 180 - 120 3x = 60 x = 20 Therefore, the value of x is 20. Marks Number of Students 0 - 10 25 10 - 20 x = 20 20 - 30 30 30 - 40 2×20 = 40 40 - 50 65 Therefore, the complete data is, Marks Number of Students 0 - 10 25 10 - 20 20 20 - 30 30 30 - 40 40 40 - 50 65 The histogram representing the above information is as shown below. |
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