(i) The amount of air present in a cylinder when a vacuum pump removes

1.	(i) The amount of air present in a cylinder when a vacuum pump removes - of theair remaining in the cylinder at a time.
Answer» Let us assume, initial quantity of air = 1 Therefore, quantity removed in first step = ¼ Remaining quantity after first step =1−1/4=3/4 Quantity removed in second step =3/4×1/4=3/16=3/4×1/4=3/16 Remaining quantity after second step =3/4−3/16=12−3/16=9/16 Here each subsequent term is not obtained by adding a fixed number to the previous term. Hence, it is not an AP. Like if you find it useful

(i) The amount of air present in a cylinder when a vacuum pump removes - of theair remaining in the cylinder at a time.

Answer»

Let us assume, initial quantity of air = 1

Therefore, quantity removed in first step = ¼

Remaining quantity after first step

=1−1/4=3/4

Quantity removed in second step

=3/4×1/4=3/16=3/4×1/4=3/16

Remaining quantity after second step

=3/4−3/16=12−3/16=9/16

Here each subsequent term is not obtained by adding a fixed number to the previous term.

Hence, it is not an AP.

Like if you find it useful