Saved Bookmarks
| 1. |
(i) sin6θ+cos6θ=1−3sin2θcos2θ (ii) sin4θ−cos4θ=sin2θ−cos2θ (iii) cosec4θ−cosec2θ=cot4θ+cot2θ |
|
Answer» (i) sin6θ+cos6θ=1−3sin2θcos2θ (ii) sin4θ−cos4θ=sin2θ−cos2θ (iii) cosec4θ−cosec2θ=cot4θ+cot2θ |
|