Saved Bookmarks
| 1. |
i n ^ { 2 } 34 ^ { 0 } + \operatorname { sin } ^ { 2 } 56 ^ { \circ } + 2 \operatorname { tan } 18 ^ { \circ } \operatorname { tan } 72 ^ { \circ } - \operatorname { cot } ^ { 2 } 30 ^ { \circ } |
|
Answer» go and ask this question to your teacher 👌 sin²34°+ sin²(90°- 56°)+ 2tan18°tan(90°− 72°)− cot²30°. =sin²34°+cos²34°+2tan18°cot18°-cot²30 = 1+2-(√3)² = 1+2-3 = 0 But? 😐😐gggggg |
|