1.

i n ^ { 2 } 34 ^ { 0 } + \operatorname { sin } ^ { 2 } 56 ^ { \circ } + 2 \operatorname { tan } 18 ^ { \circ } \operatorname { tan } 72 ^ { \circ } - \operatorname { cot } ^ { 2 } 30 ^ { \circ }

Answer»

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sin²34°+ sin²(90°- 56°)+ 2tan18°tan(90°− 72°)− cot²30°.

=sin²34°+cos²34°+2tan18°cot18°-cot²30

= 1+2-(√3)²

= 1+2-3

= 0

But?

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