.......................I Know u come for points...but plss answer firs

1.	.......................I Know u come for points...but plss answer first..calculate the number of moles in a) 1.11 gram of calcium chlorideb) 1.5 into 10^30 molecules of ammoniacorrect answer-brainlist+5 thanks
Answer» Answer:- (a) 0.01 mole is there in 1.11g of Calcium Chloride. (B) 2.5×10⁶ moles are there in 1.5×10³⁰ molecules of AMMONIA. Explanation:- For 1.11g of Calcium Chloride :- • MOLAR mass of Calcium (CA) = 40g/mol • Molar mass of Chlorine (Cl) = 35.5g/mol Hence, molar mass of CaCl2 :- = 40 + 35.5×2 = 40 + 71 = 111g/mol Number of moles :- = Given Mass/Molar mass = 1.11/111 = 0.01 mole For 1.5×10³⁰ molecules of Ammonia :- • Avogadro Number = 6.022×10²³ Number of moles :- = No of molecules/Avogadro Number = 1.5×10³⁰/6.022×10²³ = 0.25×10⁷ = 2.5×10⁶ molecules

.......................I Know u come for points...but plss answer first..calculate the number of moles in a) 1.11 gram of calcium chlorideb) 1.5 into 10^30 molecules of ammoniacorrect answer-brainlist+5 thanks

Answer»

(a) 0.01 mole is there in 1.11g of Calcium

Chloride.

(B) 2.5×10⁶ moles are there in 1.5×10³⁰

molecules of AMMONIA.

For 1.11g of Calcium Chloride :-

• MOLAR mass of Calcium (CA) = 40g/mol

• Molar mass of Chlorine (Cl) = 35.5g/mol

Hence, molar mass of CaCl2 :-

= 40 + 35.5×2

= 40 + 71

= 111g/mol

Number of moles :-

= Given Mass/Molar mass

= 1.11/111

= 0.01 mole

For 1.5×10³⁰ molecules of Ammonia :-

• Avogadro Number = 6.022×10²³

Number of moles :-

= No of molecules/Avogadro Number

= 1.5×10³⁰/6.022×10²³

= 0.25×10⁷

= 2.5×10⁶ molecules