(i) In AABC, DE | AB,DC =2BDA(ACDE)=20 cm thenfind A(OABDE)

1.	(i) In AABC, DE \| AB,DC =2BDA(ACDE)=20 cm thenfind A(OABDE)
Answer» Answer: The basic proportionality theorem STATES that if a LINE is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it DIVIDES the two sides in the same ratio. It is given that AD=8 CM, AB=12 cm and AE=12 cm. Using the basic proportionality theorem, we have AB AD = AC AE = BC DE ⇒ AB AD = AC AE ⇒ 12 8 = AC 12 ⇒8AC=12×12 ⇒8AC=144 ⇒AC= 8 144 =18 Now, CE=AC−AE=18−12=6 cm Hence, CE=6 cm.

Answer»

Answer:

The basic proportionality theorem STATES that if a LINE is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it DIVIDES the two sides in the same ratio.

It is given that AD=8 CM, AB=12 cm and AE=12 cm.

Using the basic proportionality theorem, we have

⇒

⇒8AC=12×12

⇒8AC=144

⇒AC=

144

=18

Now, CE=AC−AE=18−12=6 cm

Hence, CE=6 cm.

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(i) In AABC, DE | AB,DC =2BDA(ACDE)=20 cm thenfind A(OABDE)​

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(i) In AABC, DE | AB,DC =2BDA(ACDE)=20 cm thenfind A(OABDE)