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(i) Calculate the gram molecular mass of NH_(3) |
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Answer» Solution :(i) Atomic MASS of N=14 Gram molecular mass of `NH_(3)=(14xx1)+(1xx3)` =`14+3=17 g` (ii) `"Mass PERCENTAGE"=("Mass of the solvent")/("Mass of the solute+Mass of the solvent")` =`(500)/(500+50)xx10` =`(500)/(550)xx100=90.90%` (iii) Mass of water =0.18 g `"Number of moles"=("Mass")/("Molecular Mass")` =`(0.18)/(18)=0.01` MOLE `"Number of MOLECULES"="No. of moles"xx"Avogadro number"` =`0.01xx6.023xx10^(23)` =`0.06023xx10^(23)` =`6.023xx10^(21)` molecules |
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