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I. Assuming the atomic weight of a metal M to be 56, find the empirical formulaof its oxide containing 70.0% of M. |
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Answer» M2O3.Explanation:From the question we know that the atomic WEIGHT of metal M is given as 56 gram. Again we get that the metal oxide contains 70% of the metal, so the remaining (100-70)=30% will be the oxide present in it.So, in 1 ATOM of metal if we TAKE N atoms of oxygen then the mass proportion of the metal and the oxygen will be :-56:n*16 = 70:30.16n=56*30/70.n=24/16 = 1.5. So, the whole NUMBER ratio will be 2:3.Therefore, we get that there will be two atoms of metal against the 3 atoms of Oxygen. So, the empirical formulae will be M2O3. |
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