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(i) An element X-belongs to the second period of p-block. It has 6 electrons in the outermost shell. Name the element. (ii) How do the electronic configuration of the elements with Z = 107 to 109 differ from one another? (iii) Rn (Z = 86) is the last noble gas discovered. Predict what will be the atomic number of the next noble gas to be discovered. Write its symbol. |
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Answer» (i) The outermost configuration of the element = 2s2 2p4 (as it has 6 electrons in the outermost shell) \(\therefore\) Electronic configuration of the element = 1s2 , 2s2 2p4 \(\therefore\) Atomic number = 2+ 2 + 4 = 8 Hence, the element is oxygen. (ii) Element with Z = 107 has five, Z = 108 has six electrons while Z = 109 has seven 6d-eletrons. Hence, these elements differ in the number of electrons in the 6dsubshell. (iii) Z = 86 Atomic number of next noble gas = 86 + 32 = 118 Its symbol is Uuo. |
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