I am trying to solve for 2001 to the power of 2.

1.	I am trying to solve for 2001 to the power of 2.
Answer» Answer: Step-by-step EXPLANATION: (2001^2) we will use identity for it , (2000+1)^2 we know, (a+b)^2 = a^2 + 2ab + b^2 i.e. (2000+1)^2 = (2000)^2 + 2(2000)(1) + (1)^2 that is, 4000000 + 4000 + 1 = 4004001 hope you UNDERSTOOD

Answer»

Answer:

Step-by-step EXPLANATION:

(2001^2)

we will use identity for it ,

(2000+1)^2

we know,

(a+b)^2 = a^2 + 2ab + b^2

i.e.

(2000+1)^2 = (2000)^2 + 2(2000)(1) + (1)^2

that is,

4000000 + 4000 + 1

= 4004001

hope you UNDERSTOOD

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I am trying to solve for 2001 to the power of 2.

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