i*acos(cos((2*pi)/3)) %2B Abs(C)*asin(sin((2*pi)/3)) – InterviewSolution

1.	iacos(cos((2pi)/3)) %2B Abs(C)asin(sin((2pi)/3))
Answer» cos^-1{cos(π-π/3)}+ sin^-1{sin(π-π/3)}=cos^-1{cos(-π/3)}+sin^-1(sinπ/3)=-π/3+π/3=0

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