i) A tree is broken by the wind. The top of that tree struck the groun

1.	i) A tree is broken by the wind. The top of that tree struck the ground at an angleof 30Â° & at a distance of 30 m from the root. Find the height of the whole tree.
Answer» given : distance between the foot of the tree and the broken part of the tree that touches the ground = 30 m let ,the height ofstanding part of the tree be = h theheight of fallen part (forms hypotenuse) be = x then the total height of the tree will be = h + x now,tan 30 = h/30 m 1/√3 = h/30 m 30/√3 = h ⇒ h= 30/√3 m ..... 1 similarly,cos30 = 30 m/ x √3/2 = 30/ x√3x = (30)2√3x = 60 m⇒x = 60 /√3 m ......2 (we now have both value of h and x ) on adding equation1 & 2 :⇒h + x = 30 /√3 +60 /√3 =90 /√3 m = 60√3 m so , the total height of the tree is 60√3 m . Hit like if you find it useful!

i) A tree is broken by the wind. The top of that tree struck the ground at an angleof 30Â° & at a distance of 30 m from the root. Find the height of the whole tree.

Answer»

given : distance between the foot of the tree and the broken part of the tree that touches the ground = 30 m

let ,the height ofstanding part of the tree be = h

theheight of fallen part (forms hypotenuse) be = x

then the total height of the tree will be = h + x

now,tan 30 = h/30 m 1/√3 = h/30 m 30/√3 = h ⇒ h= 30/√3 m ..... 1

similarly,cos30 = 30 m/ x √3/2 = 30/ x√3x = (30)2√3x = 60 m⇒x = 60 /√3 m ......2

(we now have both value of h and x )

on adding equation1 & 2 :⇒h + x = 30 /√3 +60 /√3 =90 /√3 m = 60√3 m

so , the total height of the tree is 60√3 m .

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