(i)A blue coloured compound `(A)` on heating gives two product `(B)` & `( C)`. (ii)A metal `(D)` is deposited on passing hydrogen through heated `(B)`. (iii)The solution of `(B)` in `HCl` on treatment with the `[Fe(CN)_(6)]^(4-)` gives a chocolate brown coloured precipitate of compound `(E)`. (iv)`(C )` turns lime water milky which disappears on continuous passage of `(C )` forming a compound `(F)`. Identigfy `(A)` to `(F)` and give chemical equations for the reactions at step (i) to (iv).

(i)A blue coloured compound `(A)` on heating gives two product `(B)` &

1.	(i)A blue coloured compound `(A)` on heating gives two product `(B)` & `( C)`. (ii)A metal `(D)` is deposited on passing hydrogen through heated `(B)`. (iii)The solution of `(B)` in `HCl` on treatment with the `[Fe(CN)_(6)]^(4-)` gives a chocolate brown coloured precipitate of compound `(E)`. (iv)`(C )` turns lime water milky which disappears on continuous passage of `(C )` forming a compound `(F)`. Identigfy `(A)` to `(F)` and give chemical equations for the reactions at step (i) to (iv).
Answer» Correct Answer - A=`CuCO_(3)`, B=`CuO` , C=`CO_(2)` , D=`Cu` , E=`Cu_(2)[Fe(CN)_(6)]`,F=`Ca(HCO_(3))_(2)` (i)`CuCO_(3)(A) overset(Delta)toCuO (B)+CO_(2) (C )`, (ii)`CuO (B) +H_(2) overset(Delta)toCudarr(D)+H_(2)O` (iii)`2Cu^(2+)+[Fe(CN)_(6)]^(4-) to 2Cu_(2) [Fe(CN)_(6)]darr`(chocolate brown) `(E)` (iv)`CO_(2)+Ca(OH)_(2)toCaCO_(3)darr+H_(2)O , CaCO_(3)+H_(2)O+CO_(2)toCa(HCO_(3))_(2)`(soluble)

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