1.

(i) 3x2 - 4 V3 x+4 = 0​

Answer»

GIVEN :-

  • 3x² - 4√3x + 4 = 0.

TO FIND :-

  • The value of x.

SOLUTION :-

\implies  \sf \: 3x ^{2}  - 4 \sqrt{3} x + 4 = 0

By SPLITTING the MIDDLE TERM,

\implies  \sf \: 3x ^{2} - \bigg (2 \sqrt{3}  + 2 \sqrt{3} \bigg )x + 4 = 0 \\

\implies  \sf \: 3x ^{2} - 2 \sqrt{3}x  - 2 \sqrt{3}x + 4 = 0 \\

\implies  \sf \:  \sqrt{3} x \bigg( \sqrt{3} x - 2 \bigg) - 2 \bigg( \sqrt{3} x - 2 \bigg) = 0 \\

\implies  \sf \: \bigg( \sqrt{3} x - 2 \bigg) \bigg( \sqrt{3} x - 2 \bigg) = 0 \\

\implies  \sf \:   \bigg( \sqrt{3} x - 2 \bigg) ^{2}  = 0 \\

\implies  \sf \:  \sqrt{3}x  - 2 =  \sqrt{0}  \\

\implies  \sf \:  \sqrt{3} x - 2 = 0 \\

\implies  \sf \:  \sqrt{3} x = 2 \\

\implies  \underline{ \boxed{ \sf \: x =  \dfrac{2}{ \sqrt{3} } }}

The above quadratic equation has REAL and equal roots .



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