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(i) (3x - 1)^2 – (3x - 2) (3x + 1) |
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Answer» Step-by-step explanation: (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6X + 1 - (9x^2 + 3x - 6x -2) (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2 (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 or.... (3x-1)^2 - (3x-2)(3x+1) (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2) (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2 (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 If this was an equation (3x-1)^2 - (3x-2)(3x+1) = 0, (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 If this was an equation (3x-1)^2 - (3x-2)(3x+1) = 0,in that case we can FIND the solution of this equation by (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 If this was an equation (3x-1)^2 - (3x-2)(3x+1) = 0,in that case we can find the solution of this equation by-3x + 3 = 0 (3x-1)^2 - (3x-2)(3x+1)= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2= -3x + 3 If this was an equation (3x-1)^2 - (3x-2)(3x+1) = 0,in that case we can find the solution of this equation by-3x + 3 = 0x = 1 |
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