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((i %2B 1)/(-i %2B 1))^3 - (-i %2B 1)^3/(i %2B 1)^3=a %2B b*i |
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Answer» (1+i/1-i)³-(1-i/1+i)³=x+iyor, x+iy=[(1³+3i+3i²+i³)/(1³-3i+3i²-i³)]-[(1³-3i+3i²-i³)/(1³+3i+3i²+i³)]or, x+iy={1+3i+3(-1)+(-1).i}/{1-3i+3(-1)-(-1).i}-{1-3i+3(-1)-(-1).i}/{1+3i+3(-1)+(-1).i}or, x+iy=(1+3i-3-i)/(1-3i-3+i)-(1-3i-3+i)/(1+3i-3-i)or, x+iy=(-2+2i)/(-2-2i)-(-2-2i)/(-2+2i)or, x+iy={(-2)(1-i)/(-2)(1+i)}-{(-2)(1+i)/(-2)(1-i)}or, x+iy=[(1-i/1+i)-(1+i/1-i)or, x+iy={(1-i)²-(1+i)²}/{(1)²-(i)²}or, x+iy=(1-2i+i²-1-2i-i²)/{1-(-1)}or, x+iy=(-4i)/(1+1)or, x+iy=-4i/2or, x+iy=-2ior, x+iy=0+i.(-2)where x=0 and y=-2 Let a and b be X and y option 3 is the correct answer of the given question |
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