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Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place `Zn+2HClrarrZnCl_(2)+H_(2)` Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3u |
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Answer» `underset(65.u (65.3g))(Zn(s)+2HCl(aq))overset("S.T.P")(rarr)Zn.Cl_(2)(aq)+underset(22.7L)(H_(2)(g))` 65.3 g of zinc evolve hydrogen gas at S.T.P = 22.7 L 32.65 g of zinc evolve hydrogen gas at S.T.P `= ((32.65g))/((65.3g))xx(22.7L)=11.35L`. |
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